3.2217 \(\int \frac{d+e x}{(a+b x+c x^2)^4} \, dx\)

Optimal. Leaf size=173 \[ \frac{20 c^2 (2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{7/2}}-\frac{5 c (b+2 c x) (2 c d-b e)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}+\frac{5 (b+2 c x) (2 c d-b e)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac{-2 a e+x (2 c d-b e)+b d}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3} \]

[Out]

-(b*d - 2*a*e + (2*c*d - b*e)*x)/(3*(b^2 - 4*a*c)*(a + b*x + c*x^2)^3) + (5*(2*c*d - b*e)*(b + 2*c*x))/(6*(b^2
- 4*a*c)^2*(a + b*x + c*x^2)^2) - (5*c*(2*c*d - b*e)*(b + 2*c*x))/((b^2 - 4*a*c)^3*(a + b*x + c*x^2)) + (20*c
^2*(2*c*d - b*e)*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(b^2 - 4*a*c)^(7/2)

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Rubi [A]  time = 0.0738182, antiderivative size = 173, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {638, 614, 618, 206} \[ \frac{20 c^2 (2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{7/2}}-\frac{5 c (b+2 c x) (2 c d-b e)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}+\frac{5 (b+2 c x) (2 c d-b e)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac{-2 a e+x (2 c d-b e)+b d}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3} \]

Antiderivative was successfully verified.

[In]

Int[(d + e*x)/(a + b*x + c*x^2)^4,x]

[Out]

-(b*d - 2*a*e + (2*c*d - b*e)*x)/(3*(b^2 - 4*a*c)*(a + b*x + c*x^2)^3) + (5*(2*c*d - b*e)*(b + 2*c*x))/(6*(b^2
- 4*a*c)^2*(a + b*x + c*x^2)^2) - (5*c*(2*c*d - b*e)*(b + 2*c*x))/((b^2 - 4*a*c)^3*(a + b*x + c*x^2)) + (20*c
^2*(2*c*d - b*e)*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(b^2 - 4*a*c)^(7/2)

Rule 638

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b*d - 2*a*e + (2*c*d -
b*e)*x)*(a + b*x + c*x^2)^(p + 1))/((p + 1)*(b^2 - 4*a*c)), x] - Dist[((2*p + 3)*(2*c*d - b*e))/((p + 1)*(b^2
- 4*a*c)), Int[(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[2*c*d - b*e, 0] && NeQ[b^
2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[p, -3/2]

Rule 614

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b + 2*c*x)*(a + b*x + c*x^2)^(p + 1))/((p +
1)*(b^2 - 4*a*c)), x] - Dist[(2*c*(2*p + 3))/((p + 1)*(b^2 - 4*a*c)), Int[(a + b*x + c*x^2)^(p + 1), x], x] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[p, -3/2] && IntegerQ[4*p]

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{d+e x}{\left (a+b x+c x^2\right )^4} \, dx &=-\frac{b d-2 a e+(2 c d-b e) x}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}-\frac{(5 (2 c d-b e)) \int \frac{1}{\left (a+b x+c x^2\right )^3} \, dx}{3 \left (b^2-4 a c\right )}\\ &=-\frac{b d-2 a e+(2 c d-b e) x}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}+\frac{5 (2 c d-b e) (b+2 c x)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}+\frac{(5 c (2 c d-b e)) \int \frac{1}{\left (a+b x+c x^2\right )^2} \, dx}{\left (b^2-4 a c\right )^2}\\ &=-\frac{b d-2 a e+(2 c d-b e) x}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}+\frac{5 (2 c d-b e) (b+2 c x)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac{5 c (2 c d-b e) (b+2 c x)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}-\frac{\left (10 c^2 (2 c d-b e)\right ) \int \frac{1}{a+b x+c x^2} \, dx}{\left (b^2-4 a c\right )^3}\\ &=-\frac{b d-2 a e+(2 c d-b e) x}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}+\frac{5 (2 c d-b e) (b+2 c x)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac{5 c (2 c d-b e) (b+2 c x)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}+\frac{\left (20 c^2 (2 c d-b e)\right ) \operatorname{Subst}\left (\int \frac{1}{b^2-4 a c-x^2} \, dx,x,b+2 c x\right )}{\left (b^2-4 a c\right )^3}\\ &=-\frac{b d-2 a e+(2 c d-b e) x}{3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^3}+\frac{5 (2 c d-b e) (b+2 c x)}{6 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^2}-\frac{5 c (2 c d-b e) (b+2 c x)}{\left (b^2-4 a c\right )^3 \left (a+b x+c x^2\right )}+\frac{20 c^2 (2 c d-b e) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{7/2}}\\ \end{align*}

Mathematica [A]  time = 0.21643, size = 168, normalized size = 0.97 \[ \frac{\frac{120 c^2 (b e-2 c d) \tan ^{-1}\left (\frac{b+2 c x}{\sqrt{4 a c-b^2}}\right )}{\sqrt{4 a c-b^2}}-\frac{5 \left (b^2-4 a c\right ) (b+2 c x) (b e-2 c d)}{(a+x (b+c x))^2}+\frac{2 \left (b^2-4 a c\right )^2 (2 a e-b d+b e x-2 c d x)}{(a+x (b+c x))^3}+\frac{30 c (b+2 c x) (b e-2 c d)}{a+x (b+c x)}}{6 \left (b^2-4 a c\right )^3} \]

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)/(a + b*x + c*x^2)^4,x]

[Out]

((2*(b^2 - 4*a*c)^2*(-(b*d) + 2*a*e - 2*c*d*x + b*e*x))/(a + x*(b + c*x))^3 - (5*(b^2 - 4*a*c)*(-2*c*d + b*e)*
(b + 2*c*x))/(a + x*(b + c*x))^2 + (30*c*(-2*c*d + b*e)*(b + 2*c*x))/(a + x*(b + c*x)) + (120*c^2*(-2*c*d + b*
e)*ArcTan[(b + 2*c*x)/Sqrt[-b^2 + 4*a*c]])/Sqrt[-b^2 + 4*a*c])/(6*(b^2 - 4*a*c)^3)

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Maple [B]  time = 0.153, size = 369, normalized size = 2.1 \begin{align*}{\frac{bd-2\,ae+ \left ( -be+2\,cd \right ) x}{ \left ( 12\,ac-3\,{b}^{2} \right ) \left ( c{x}^{2}+bx+a \right ) ^{3}}}-{\frac{5\,bcxe}{3\, \left ( 4\,ac-{b}^{2} \right ) ^{2} \left ( c{x}^{2}+bx+a \right ) ^{2}}}+{\frac{10\,{c}^{2}xd}{3\, \left ( 4\,ac-{b}^{2} \right ) ^{2} \left ( c{x}^{2}+bx+a \right ) ^{2}}}-{\frac{5\,{b}^{2}e}{6\, \left ( 4\,ac-{b}^{2} \right ) ^{2} \left ( c{x}^{2}+bx+a \right ) ^{2}}}+{\frac{5\,bcd}{3\, \left ( 4\,ac-{b}^{2} \right ) ^{2} \left ( c{x}^{2}+bx+a \right ) ^{2}}}-10\,{\frac{{c}^{2}xbe}{ \left ( 4\,ac-{b}^{2} \right ) ^{3} \left ( c{x}^{2}+bx+a \right ) }}+20\,{\frac{x{c}^{3}d}{ \left ( 4\,ac-{b}^{2} \right ) ^{3} \left ( c{x}^{2}+bx+a \right ) }}-5\,{\frac{{b}^{2}ce}{ \left ( 4\,ac-{b}^{2} \right ) ^{3} \left ( c{x}^{2}+bx+a \right ) }}+10\,{\frac{b{c}^{2}d}{ \left ( 4\,ac-{b}^{2} \right ) ^{3} \left ( c{x}^{2}+bx+a \right ) }}-20\,{\frac{b{c}^{2}e}{ \left ( 4\,ac-{b}^{2} \right ) ^{7/2}}\arctan \left ({\frac{2\,cx+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) }+40\,{\frac{{c}^{3}d}{ \left ( 4\,ac-{b}^{2} \right ) ^{7/2}}\arctan \left ({\frac{2\,cx+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)/(c*x^2+b*x+a)^4,x)

[Out]

1/3*(b*d-2*a*e+(-b*e+2*c*d)*x)/(4*a*c-b^2)/(c*x^2+b*x+a)^3-5/3/(4*a*c-b^2)^2/(c*x^2+b*x+a)^2*x*c*b*e+10/3/(4*a
*c-b^2)^2/(c*x^2+b*x+a)^2*x*c^2*d-5/6/(4*a*c-b^2)^2/(c*x^2+b*x+a)^2*b^2*e+5/3/(4*a*c-b^2)^2/(c*x^2+b*x+a)^2*b*
c*d-10/(4*a*c-b^2)^3*c^2/(c*x^2+b*x+a)*x*b*e+20/(4*a*c-b^2)^3*c^3/(c*x^2+b*x+a)*x*d-5/(4*a*c-b^2)^3*c/(c*x^2+b
*x+a)*b^2*e+10/(4*a*c-b^2)^3*c^2/(c*x^2+b*x+a)*b*d-20/(4*a*c-b^2)^(7/2)*c^2*arctan((2*c*x+b)/(4*a*c-b^2)^(1/2)
)*b*e+40/(4*a*c-b^2)^(7/2)*c^3*arctan((2*c*x+b)/(4*a*c-b^2)^(1/2))*d

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)/(c*x^2+b*x+a)^4,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [B]  time = 2.34774, size = 4157, normalized size = 24.03 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)/(c*x^2+b*x+a)^4,x, algorithm="fricas")

[Out]

[-1/6*(60*(2*(b^2*c^5 - 4*a*c^6)*d - (b^3*c^4 - 4*a*b*c^5)*e)*x^5 + 150*(2*(b^3*c^4 - 4*a*b*c^5)*d - (b^4*c^3
- 4*a*b^2*c^4)*e)*x^4 + 10*(2*(11*b^4*c^3 - 28*a*b^2*c^4 - 64*a^2*c^5)*d - (11*b^5*c^2 - 28*a*b^3*c^3 - 64*a^2
*b*c^4)*e)*x^3 + 15*(2*(b^5*c^2 + 12*a*b^3*c^3 - 64*a^2*b*c^4)*d - (b^6*c + 12*a*b^4*c^2 - 64*a^2*b^2*c^3)*e)*
x^2 - 60*(2*a^3*c^3*d - a^3*b*c^2*e + (2*c^6*d - b*c^5*e)*x^6 + 3*(2*b*c^5*d - b^2*c^4*e)*x^5 + 3*(2*(b^2*c^4
+ a*c^5)*d - (b^3*c^3 + a*b*c^4)*e)*x^4 + (2*(b^3*c^3 + 6*a*b*c^4)*d - (b^4*c^2 + 6*a*b^2*c^3)*e)*x^3 + 3*(2*(
a*b^2*c^3 + a^2*c^4)*d - (a*b^3*c^2 + a^2*b*c^3)*e)*x^2 + 3*(2*a^2*b*c^3*d - a^2*b^2*c^2*e)*x)*sqrt(b^2 - 4*a*
c)*log((2*c^2*x^2 + 2*b*c*x + b^2 - 2*a*c + sqrt(b^2 - 4*a*c)*(2*c*x + b))/(c*x^2 + b*x + a)) + 2*(b^7 - 17*a*
b^5*c + 118*a^2*b^3*c^2 - 264*a^3*b*c^3)*d + (a*b^6 - 22*a^2*b^4*c + 8*a^3*b^2*c^2 + 256*a^4*c^3)*e - 3*(2*(b^
6*c - 22*a*b^4*c^2 + 28*a^2*b^2*c^3 + 176*a^3*c^4)*d - (b^7 - 22*a*b^5*c + 28*a^2*b^3*c^2 + 176*a^3*b*c^3)*e)*
x)/(a^3*b^8 - 16*a^4*b^6*c + 96*a^5*b^4*c^2 - 256*a^6*b^2*c^3 + 256*a^7*c^4 + (b^8*c^3 - 16*a*b^6*c^4 + 96*a^2
*b^4*c^5 - 256*a^3*b^2*c^6 + 256*a^4*c^7)*x^6 + 3*(b^9*c^2 - 16*a*b^7*c^3 + 96*a^2*b^5*c^4 - 256*a^3*b^3*c^5 +
256*a^4*b*c^6)*x^5 + 3*(b^10*c - 15*a*b^8*c^2 + 80*a^2*b^6*c^3 - 160*a^3*b^4*c^4 + 256*a^5*c^6)*x^4 + (b^11 -
10*a*b^9*c + 320*a^3*b^5*c^3 - 1280*a^4*b^3*c^4 + 1536*a^5*b*c^5)*x^3 + 3*(a*b^10 - 15*a^2*b^8*c + 80*a^3*b^6
*c^2 - 160*a^4*b^4*c^3 + 256*a^6*c^5)*x^2 + 3*(a^2*b^9 - 16*a^3*b^7*c + 96*a^4*b^5*c^2 - 256*a^5*b^3*c^3 + 256
*a^6*b*c^4)*x), -1/6*(60*(2*(b^2*c^5 - 4*a*c^6)*d - (b^3*c^4 - 4*a*b*c^5)*e)*x^5 + 150*(2*(b^3*c^4 - 4*a*b*c^5
)*d - (b^4*c^3 - 4*a*b^2*c^4)*e)*x^4 + 10*(2*(11*b^4*c^3 - 28*a*b^2*c^4 - 64*a^2*c^5)*d - (11*b^5*c^2 - 28*a*b
^3*c^3 - 64*a^2*b*c^4)*e)*x^3 + 15*(2*(b^5*c^2 + 12*a*b^3*c^3 - 64*a^2*b*c^4)*d - (b^6*c + 12*a*b^4*c^2 - 64*a
^2*b^2*c^3)*e)*x^2 - 120*(2*a^3*c^3*d - a^3*b*c^2*e + (2*c^6*d - b*c^5*e)*x^6 + 3*(2*b*c^5*d - b^2*c^4*e)*x^5
+ 3*(2*(b^2*c^4 + a*c^5)*d - (b^3*c^3 + a*b*c^4)*e)*x^4 + (2*(b^3*c^3 + 6*a*b*c^4)*d - (b^4*c^2 + 6*a*b^2*c^3)
*e)*x^3 + 3*(2*(a*b^2*c^3 + a^2*c^4)*d - (a*b^3*c^2 + a^2*b*c^3)*e)*x^2 + 3*(2*a^2*b*c^3*d - a^2*b^2*c^2*e)*x)
*sqrt(-b^2 + 4*a*c)*arctan(-sqrt(-b^2 + 4*a*c)*(2*c*x + b)/(b^2 - 4*a*c)) + 2*(b^7 - 17*a*b^5*c + 118*a^2*b^3*
c^2 - 264*a^3*b*c^3)*d + (a*b^6 - 22*a^2*b^4*c + 8*a^3*b^2*c^2 + 256*a^4*c^3)*e - 3*(2*(b^6*c - 22*a*b^4*c^2 +
28*a^2*b^2*c^3 + 176*a^3*c^4)*d - (b^7 - 22*a*b^5*c + 28*a^2*b^3*c^2 + 176*a^3*b*c^3)*e)*x)/(a^3*b^8 - 16*a^4
*b^6*c + 96*a^5*b^4*c^2 - 256*a^6*b^2*c^3 + 256*a^7*c^4 + (b^8*c^3 - 16*a*b^6*c^4 + 96*a^2*b^4*c^5 - 256*a^3*b
^2*c^6 + 256*a^4*c^7)*x^6 + 3*(b^9*c^2 - 16*a*b^7*c^3 + 96*a^2*b^5*c^4 - 256*a^3*b^3*c^5 + 256*a^4*b*c^6)*x^5
+ 3*(b^10*c - 15*a*b^8*c^2 + 80*a^2*b^6*c^3 - 160*a^3*b^4*c^4 + 256*a^5*c^6)*x^4 + (b^11 - 10*a*b^9*c + 320*a^
3*b^5*c^3 - 1280*a^4*b^3*c^4 + 1536*a^5*b*c^5)*x^3 + 3*(a*b^10 - 15*a^2*b^8*c + 80*a^3*b^6*c^2 - 160*a^4*b^4*c
^3 + 256*a^6*c^5)*x^2 + 3*(a^2*b^9 - 16*a^3*b^7*c + 96*a^4*b^5*c^2 - 256*a^5*b^3*c^3 + 256*a^6*b*c^4)*x)]

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Sympy [B]  time = 4.3648, size = 1062, normalized size = 6.14 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)/(c*x**2+b*x+a)**4,x)

[Out]

10*c**2*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d)*log(x + (-2560*a**4*c**6*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*
c*d) + 2560*a**3*b**2*c**5*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) - 960*a**2*b**4*c**4*sqrt(-1/(4*a*c - b**2
)**7)*(b*e - 2*c*d) + 160*a*b**6*c**3*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) - 10*b**8*c**2*sqrt(-1/(4*a*c -
b**2)**7)*(b*e - 2*c*d) + 10*b**2*c**2*e - 20*b*c**3*d)/(20*b*c**3*e - 40*c**4*d)) - 10*c**2*sqrt(-1/(4*a*c -
b**2)**7)*(b*e - 2*c*d)*log(x + (2560*a**4*c**6*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) - 2560*a**3*b**2*c**
5*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) + 960*a**2*b**4*c**4*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) - 160
*a*b**6*c**3*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d) + 10*b**8*c**2*sqrt(-1/(4*a*c - b**2)**7)*(b*e - 2*c*d)
+ 10*b**2*c**2*e - 20*b*c**3*d)/(20*b*c**3*e - 40*c**4*d)) - (64*a**3*c**2*e + 18*a**2*b**2*c*e - 132*a**2*b*c
**2*d - a*b**4*e + 26*a*b**3*c*d - 2*b**5*d + x**5*(60*b*c**4*e - 120*c**5*d) + x**4*(150*b**2*c**3*e - 300*b*
c**4*d) + x**3*(160*a*b*c**3*e - 320*a*c**4*d + 110*b**3*c**2*e - 220*b**2*c**3*d) + x**2*(240*a*b**2*c**2*e -
480*a*b*c**3*d + 15*b**4*c*e - 30*b**3*c**2*d) + x*(132*a**2*b*c**2*e - 264*a**2*c**3*d + 54*a*b**3*c*e - 108
*a*b**2*c**2*d - 3*b**5*e + 6*b**4*c*d))/(384*a**6*c**3 - 288*a**5*b**2*c**2 + 72*a**4*b**4*c - 6*a**3*b**6 +
x**6*(384*a**3*c**6 - 288*a**2*b**2*c**5 + 72*a*b**4*c**4 - 6*b**6*c**3) + x**5*(1152*a**3*b*c**5 - 864*a**2*b
**3*c**4 + 216*a*b**5*c**3 - 18*b**7*c**2) + x**4*(1152*a**4*c**5 + 288*a**3*b**2*c**4 - 648*a**2*b**4*c**3 +
198*a*b**6*c**2 - 18*b**8*c) + x**3*(2304*a**4*b*c**4 - 1344*a**3*b**3*c**3 + 144*a**2*b**5*c**2 + 36*a*b**7*c
- 6*b**9) + x**2*(1152*a**5*c**4 + 288*a**4*b**2*c**3 - 648*a**3*b**4*c**2 + 198*a**2*b**6*c - 18*a*b**8) + x
*(1152*a**5*b*c**3 - 864*a**4*b**3*c**2 + 216*a**3*b**5*c - 18*a**2*b**7))

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Giac [B]  time = 1.18469, size = 510, normalized size = 2.95 \begin{align*} -\frac{20 \,{\left (2 \, c^{3} d - b c^{2} e\right )} \arctan \left (\frac{2 \, c x + b}{\sqrt{-b^{2} + 4 \, a c}}\right )}{{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} \sqrt{-b^{2} + 4 \, a c}} - \frac{120 \, c^{5} d x^{5} - 60 \, b c^{4} x^{5} e + 300 \, b c^{4} d x^{4} - 150 \, b^{2} c^{3} x^{4} e + 220 \, b^{2} c^{3} d x^{3} + 320 \, a c^{4} d x^{3} - 110 \, b^{3} c^{2} x^{3} e - 160 \, a b c^{3} x^{3} e + 30 \, b^{3} c^{2} d x^{2} + 480 \, a b c^{3} d x^{2} - 15 \, b^{4} c x^{2} e - 240 \, a b^{2} c^{2} x^{2} e - 6 \, b^{4} c d x + 108 \, a b^{2} c^{2} d x + 264 \, a^{2} c^{3} d x + 3 \, b^{5} x e - 54 \, a b^{3} c x e - 132 \, a^{2} b c^{2} x e + 2 \, b^{5} d - 26 \, a b^{3} c d + 132 \, a^{2} b c^{2} d + a b^{4} e - 18 \, a^{2} b^{2} c e - 64 \, a^{3} c^{2} e}{6 \,{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )}{\left (c x^{2} + b x + a\right )}^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)/(c*x^2+b*x+a)^4,x, algorithm="giac")

[Out]

-20*(2*c^3*d - b*c^2*e)*arctan((2*c*x + b)/sqrt(-b^2 + 4*a*c))/((b^6 - 12*a*b^4*c + 48*a^2*b^2*c^2 - 64*a^3*c^
3)*sqrt(-b^2 + 4*a*c)) - 1/6*(120*c^5*d*x^5 - 60*b*c^4*x^5*e + 300*b*c^4*d*x^4 - 150*b^2*c^3*x^4*e + 220*b^2*c
^3*d*x^3 + 320*a*c^4*d*x^3 - 110*b^3*c^2*x^3*e - 160*a*b*c^3*x^3*e + 30*b^3*c^2*d*x^2 + 480*a*b*c^3*d*x^2 - 15
*b^4*c*x^2*e - 240*a*b^2*c^2*x^2*e - 6*b^4*c*d*x + 108*a*b^2*c^2*d*x + 264*a^2*c^3*d*x + 3*b^5*x*e - 54*a*b^3*
c*x*e - 132*a^2*b*c^2*x*e + 2*b^5*d - 26*a*b^3*c*d + 132*a^2*b*c^2*d + a*b^4*e - 18*a^2*b^2*c*e - 64*a^3*c^2*e
)/((b^6 - 12*a*b^4*c + 48*a^2*b^2*c^2 - 64*a^3*c^3)*(c*x^2 + b*x + a)^3)